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x^2+55x+15=0
a = 1; b = 55; c = +15;
Δ = b2-4ac
Δ = 552-4·1·15
Δ = 2965
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{2965}}{2*1}=\frac{-55-\sqrt{2965}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{2965}}{2*1}=\frac{-55+\sqrt{2965}}{2} $
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